Multiply the whole thing by two.
x - 10 = 2x + 8
Subtract x from both sides.
-10 = x + 8
Subtract 8 from both sides.
-18 = x
Check it.
-9 - 5 = -18 + 4
-14 = -14
It checks.
9E-05x
no .05+ 25= 25.5
x + 4x = 05x = 0x = 0/5x = 0
5x + (4 - 4x) = 05x + 4 - 4x = 0x + 4 = 0Subtract 4 from each side:x = -4
y = 5x + 6At the x-intercept, y = 0 .5x + 6 = 05x = -6x = -6/5
5x2 - x - 4 = 0(5x + 4) (x - 1) = 05x + 4 = 05x = -4 ===> x = -(4/5)x - 1 = 0 ==> x = 1
Let X be the original price .05X = first discount new price is X-.05X .20(X-.05X) = 2nd discount new price is X -.05X - .20(X-.05X) new price = X - .05X -.20X + .01X = X - .24X equiv discount = .24 = 24%
15
15
5x^2 + 40x = 05x(x + 8) = 05x = 0 or x + 8 = 0x = 0 or x = -8Check:
.05x=7474/.05 = xx = 1480100% is 1480, 1/15 is 6.6666% so 6.666% of 1480 = 98.66698.6666
The answer: $1,000 was invested at %5. $2,500 was invested @ 8% It is done with a system of equations when "x" is a portion of $3,500 and "y" is a portion of $3,500: x + y = 3500AND .05x +.08y = 250 Use algebra and solve #2 for "x" as follows: .05x + .08y = 250 .05x = 250 - .08y x = 5000 - 1.6y plug the value of "x" into the first equation and solve for "y": 5000 - 1.6y + y = 3500 5000 - 3500 - 1.6y + y = 0 1500 - 1.6y + y = 0 1500 = 1.6y -y 1500 = .6y 2500 = y plug the value of "y" into the original equation and solve for "x" x + 2500 = 3500 x = 3500 - 2500 x = 1000 You can plug them both into the 2nd equation in the system to check it.