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How do you solve 3x3 magic square numbers 1-9 each row and column totals a prime number?
Wiki User
∙ 11y ago
Using the digits 1 to 9 once each, the smallest number you could make would be 6, the largest would be 24
Prime numbers in the range 6 to 24 are :-
7, 11, 13, 17, 19 & 23
The digits 1 to 9 added together come to a total of 45
What three prime numbers from the list when added together make 45
19 + 19 + 7 = 45
17 + 17 + 11 = 45
These have to be formed both horezontally and vertically
Since there is only one way to make 7 from three of the available digits (1+2+4) , this option is a non-starter
So working with two rows adding up to 17 and one adding up to 11, and similarly for columns I came up with the solution below
7 1 9
4 2 5
6 8 3
Wiki User
∙ 11y ago
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