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Q: How do you solve 4y plus 2 equals 2y plus 6?

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2y = 4x + 4y = 2x + 2

4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80

42+4y -12 = 13y -12 -2y 4y -13y+2y = 12 -12 -42 -7y = -42 y = 6

4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4

How do you solve 4y plus x equals 8

-6y + 14 + 4y = 32-2y = 32 - 14-2y = 18y = - 9

3x + 4y = 5x - 2y = 5leads to:x = 5 + 2ySo:3(5 + 2y) + 4y = 515 + 10y = 510y= -10y=-1and therefore if y = -1 then x = 3.

Here's how it is:2y + 10 = 5y - 4ySolution:2y + 10 = 1y (subtract 5y and 4y)10 = 1y - 2y10 = -1y-1(10 = -1y)y = -10

4y + 4 = 2y + 12Subtract 4 from each side of the equation:4y = 2y + 8Subtract 2y from each side:2y = 8Divide each side by 2 :y = 4

4y + 4 = 2y + 12Subtract 2y from each side of the equation:2y + 4 = 12Subtract 4 from each side:2y = 8Divide each side by 2:y = 4

(-1, 5)

(-1, 5)

(2, -1)

4

12x-4y+9z+2y =12x-2y+9z

Y=5.

(12, 1)

y=4

3x - 2y = 20 Substitute x = 4y into this equation: 3(4y) - 2y = 20 ie 12y - 2y = 20 10y = 20 so that y = 2 and then x = 4y gives x = 2*4 = 8

10x + 2y + 8z - 5x + 4z - 4y = 10x - 5x + 2y - 4y + 8z + 4z = (10 - 5)x + (2 - 4)y + (8 + 4)z = 5x - 2y + 12z

They are parallel lines.

Only if y = 1.5.

No. They are parallel.

11x + 2y

No, it equals 4y2