4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
4
(12, 1)
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
4y + 4 = 2y + 12Subtract 4 from each side of the equation:4y = 2y + 8Subtract 2y from each side:2y = 8Divide each side by 2 :y = 4
4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
42+4y -12 = 13y -12 -2y 4y -13y+2y = 12 -12 -42 -7y = -42 y = 6
4
(12, 1)
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
y=4
-6y + 14 + 4y = 32-2y = 32 - 14-2y = 18y = - 9
4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80
x = 12, y = 1
x = 12 and y = 1 (12, 1)
4y + 4 = 2y + 12Subtract 4 from each side of the equation:4y = 2y + 8Subtract 2y from each side:2y = 8Divide each side by 2 :y = 4
It is not one, but they are two perpendicular lines.