4y = 2y + 40
4y - 2y = 2y -2y +40
2y = 40
y = 20
check
4(20) = 2(20) +40
80 = 80
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2x+3y=40-2x+2y=20Since 2x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2x from both sides.3y=-2xDivide each term in the equation by 3.(3y)/(3)=-(2x)/(3)Simplify the left-hand side of the equation by canceling the common terms.y=-(2x)/(3)if you were solving for x It would be x=-(3y)/2
x = 2, and y = 0. Here's one way to solve:Multiply the second equation (both sides) by 3, then add the two equations:8x + 6y = 1612x - 6y = 24----------20x = 40 ----> x = 2, then substitute x=2 into one of the original equations:8*2 + 6y = 16 --> 6y = 0, and y=0. Check with the other equation: 4*2 - 2y = 8 ---> -2y = 0, and y = 0.
8-3x = 128 -3x = 128-8 -3x = 120 x = -40
5x+10=40 5x+10-10=40-10 5x=30 5x/5=30/5 x=6
5x+32+7x+8=180. By the laws of commutativity we can thus say that 12x+40=180. Subtracting 40 we get 12x=140. Divide by 12 and you get x=(do it yourself) This has nothing to do with calculus by the way.