5X^2 + 9X - 2 = 0
discriminant looks good for two real roots by inspection
X = - b (+/-) sqrt(b^2-4ac)/2a
a = 5
b = 9
c = - 2
X = - 9 (+/-) sqrt[9^2 - 4(5)(-2)]/2(5)
X = - 9 (+/-) sqrt(41)/10
X = [- 9 (+/-) sqrt(41)]/10
X = ~ - 0.2597
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X = ~ - 1.540
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Ugly, but true
Solve using the quadratic formula
It can be solved by using the quadratic equation formula.
You can't because it is not a quadratic equation.
I suggest you use the quadratic formula, with a = 3, b = -2, c = 7.
It can't be solved because the discriminant of the given quadratic equation is less than zero meaning it has no real roots.
Solve using the quadratic formula
The quadratic formula is used to solve the quadratic equation. Many equations in which the variable is squared can be written as a quadratic equation, and then solved with the quadratic formula.
It can be solved by using the quadratic equation formula.
-34
You can't because it is not a quadratic equation.
Using the quadratic equation formula: x = 8.42 or x = -1.42
I suggest you use the quadratic formula, with a = 3, b = -2, c = 7.
You don't need to use the quadratic formula because:- 5r2 = 80 Divide both sides by 5: x2 = 16 Square root both sides: r = 4
It can't be solved because the discriminant of the given quadratic equation is less than zero meaning it has no real roots.
x2+x-15 = 0 Using the quadratic equation formula: x = 3.405124838 or x = -4.405124838
Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.Use the quadratic formula, with a = 1, b = -10, c = 29.
Use the quadratic formula. x = -4.265564 or -0.234436