y= -2x
4x2 - 2x - 3 = 0 (2x + 1)(2x - 3) = 0 x = -(1/2) or (3/2)
many solutions
The vertex is at the origin of coordinates ... the point (0, 0).
X should be zeroas:X + 5 = 2X + 5so, 2X - X = 0 or X = 0
2x + 2x + 146 + 26 = 172 4x + 172 = 172 4x = 0 x = 0
x2-2x-3 = 0 (x+1)(x-3) = 0 x = -1 or x = 3
2x(3x+6) = 0 x = 0 or x = -2
X = 0 (zero) Y = -1 (neg 1)
x = 0 right 2x + 5 = 5 which makes 5 = 5 +2x subtract 5 from each side -5 -5 ---------- 0=0 + 2x 0= 2x substitue x 0 = 2 X 0 solve
2x+3x-2=0=5x=0+2=5x=2=5x_5=2_5=x=0.4
9x2 = 2x Get the 2x to the left side to get 9x2 - 2x = 0 Use cuadratic formula to solve for x knowing that c is 0 x = [ -b +- sqrt (b2-4ac) ]/2a