5x + 10 = 5(x+2) 6x2 + 12x = 6x(x+2) The only common factor is x+2
3x(x2 + 2x - 4)
6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.
One-houndred and thirty five.
When the given expression equals 0 then x = -1/6 and x = -6
6*3-6*2-12x v v 18 - 12-12x v v 6-24x -6 -6 something like that..
5x + 10 = 5(x+2) 6x2 + 12x = 6x(x+2) The only common factor is x+2
2(3x^2 + 6x + 2)
3x(x2 + 2x - 4)
(3x+1)(2x+4) = 6x2+4+2x+12x = 6x2+14x+4
6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.
6x2 - 12x [take out what both terms have in common] 6x(x - 2) [if you multiply 6x by both terms in the parenthesis you will get your original answer]
y = -6x2 - 12x - 1We recognize this as the equation of a parabola opening downward, but we don't need to know that in order to answer the question.At the extremes of a function (local max or min), the first derivative of the function = zero.The first derivative of the given function with respect to 'x' is dy/dx = -12x -12Set -12x - 12 = 0.-x - 1 = 0x = -1y = -6x2 - 12x - 1 = -6(1) - 12(-1) - 1 = -6 + 12 - 1 = 5
One-houndred and thirty five.
6x2 + 7x = 56x2 + 7x - 5 = 0x =[ -7 ± √[72 - 4(6)(-5)] ]/2(6)x = [-7 ± √(49 + 120)]/12x = (-7 ± √ 169)/12x = (-7 ± 13)/12x = (-7 + 13)/12 or x = (-7 - 13)/12x = 6/12 = 1/2 orx = -20/12 = - 5/3
When the given expression equals 0 then x = -1/6 and x = -6
9+6x2=21