How do you solve 5z2-33z-14?

Answer 1

5z2-33z-14 = 0

(5z + 2)(z - 7) = 0 {factored into two binomials}

5z + 2 = 0 or z - 7 = 0 {set each factor equal to 0}

5z = -2 or z = 7 {subtracted 2 and added 7, respectively}

z = -2/5 or z = 7 {divided left equation by 5}