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Q: How do you solve 8 . 2 1 9 and minus 3 . 1 2 1?

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x over x is one, so the problem would be 1-2-3/2=-5/3

(-1/6) - 2/3 = -0.8333333332

1/2 = 6/8 6/8 - 3/8 = 3/8

-3/5 To solve this, rewrite 1 as 5/5 then, 2/5 - 5/5 = -3/5

-1/3 Make them into fractions like: 2/9-5/9 Then you just solve and you get -3/9 which reduces to -1/3

3-2-1=0

2x squared minus 5x minus 3 factored is (2x+1)(x-3).

1/4 - 3/4 = -2/4 or -1/2

1 _ 2to the 3rd power and solve so it would be.... 1/8 as a fraction

The question contains an expression but not an equation. You cannot solve an expression.

3/6 - 2/6 = 1/6

2 minus 5 is -3, sooo your answer should be negative 3 over 7.

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