x over x is one, so the problem would be 1-2-3/2=-5/3
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-2, 3
so, if 2 minus Ln times 3 minus x equals 0, then 2 minus Ln times 3 equals x, therefore 2 minus Ln equals x divided by three, so Ln + X/3 = 2 therefore, (Ln + [X/3]) = 1
4/x-4 - 3/x+2 simplifies to 1/x+2
Here is your equation as you stated it: h-2-5 <= 14 You would start by subtracting 5 from 2 to give you: h-3 <= 14 Now you would add 3 to both sides to solve for h: h <= 17 This would be your final answer.
3(x+2) = x -18 3x+6 = x -18 3x -x = -18 -6 2x = -24 x = -12