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The altitude to the base of an isosceles triangle bisects it forming two right angled triangles (which are congruent).

In either of those right angled triangles, the altitude forms one leg and half the base of the original triangle forms the other. So,

tan(26) = Alt/11 or Alt = 11*tan(26) inches = 5.365 inches.

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Q: How do you solve An isosceles triangle has a base of 22 inches and its base angles each measure 26 degrees find the length of the altitude to the base?
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