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Log 3 plus logx equals 4?
log3 + logx=4 log(3x)=4 3x=10^4 x=10,000/3
How do you solve 4y plus x equals 8?
How do you solve 4y plus x equals 8
B equals 10 plus a solve for a?
Not enough information to solve
How to solve x plus y for graphing?
You cannot solve x plus y since that is an expression, not an equation (nor inequality).
How do you solve 5x plus 30?
There's nothing to solve, it's simply an expression.
What is Log3 3 plus log3 x plus 2 equals 3?
log33+log3x +2=3 log33+log3x=1 log3(3x)=1 3x=3 x=1 Other interpretation: log33+log3(x+2)=3 log3(3(x+2))=3 3(x+2)=27 x+2=9 x=7
What is x plus x plus 2 x equal 3?
log33+log3x +2=3 log33+log3x=1 log3(3x)=1 3x=3 x=1 Other interpretation: log33+log3(x+2)=3 log3(3(x+2))=3 3(x+2)=27 x+2=9 x=7
How do you solve log1 plus log2 plus log3?
log1 + log2 + log3 = log(1*2*3) = log6
How do you solve Log base 3 of 7x equals Log base 3 of 2x plus Log base 3 of 0.5?
There is not a solution. Knowing how logarithms work helps. On the right hand side you have: log3(2*x) + log3(0.5).Adding logs is equivalent to multiplying (inside the log). This becomes: log3(0.5 * 2*x) = log3(x).Subtract log3(x) from both sides: log3(7x) - log3(x) = 0.Subtracting logs is equivalent to division (inside the log): log3(7x/x) = 0.So log3(7) = 0, which is Not true. No Solution.
How do you solve this log x base 3 plus log x3 base 9 equal 0?
log3(x) + log9(x^3)=0 for any t >0 logt(x) = ln(x)/ln(t) so log9(x) = ln(x) / ln (9) = ln (x) / ( 2 * ln 3) = log3(x) /2 or log3(x) = 2 log9(x) log9(x^n) = n * log9(x) So log3(x) + log9(x^3) = log3(x) + 6 log3(x) = 7 log3(x) 7 log3(x) = 0 => log3(x) = 0 => x = 1
What is the expression with the logarithm Log 4 plus Log 3?
log4+log3=log(4x3)=log12
How do you simplify log base 3 25 plus log base 3 4 and express using base 10 logarithms?
log325 + log34 = log3(25*4) = log3(100) = log10100/log103 = 2/log103
Log 3 plus logx equals 4?
log3 + logx=4 log(3x)=4 3x=10^4 x=10,000/3
How do you solve 4y plus x equals 8?
How do you solve 4y plus x equals 8
B equals 10 plus a solve for a?
Not enough information to solve
How do you solve this logarithmic equation 2logX equals log2 plus log3X-4?
assuming the bases are the same, you can factor the log out, so you get:x^2 = 2 + 3x-4 (note that 2logx can be rewritten as logx^2 )x^2 - 3x +2 = 0You can factor this out: (x-1)(x-2) = 0so x must be one or x is two --> X=1 V X=2
How do you solve a equals b plus c plus d solve for c?
If: a = b+c+d Then: c = a-b-d
