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Q: How do you solve S squared plus 4s minus 21 equals to 0?

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X=1

2222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222

Solve using the quadratic formula

hello

x = 25 / 3squared + 5

You have to put your heart into it!

(b-4) squared

2

It can be solved by using the quadratic equation formula.

All the time

x = plus or minus 6.

minus 5

I suggest you use the quadratic formula, with a = 3, b = -2, c = 7.

Factor it. (x - 8)(x - 2) x = 2, 8

(3x-2)(x-2)

The centre is (-5, 3)

7

That won't factor neatly, so we apply the quadratic formula. x = -8 plus or minus 2 times the square root of 5 x = -3.5278640450004204 x = -12.47213595499958

(x-3)(x-2)

That factors to (a + 1)(a + b) a = -1, -b b = -a

X=-3

x = -28 / -11^2

{-1,7}

7(3y-2)-(-4y+9)

By including its plus or minus signs