Try this one.
All the sums are ' 1 '.
[8/15] [ 1/15] [ 2/5 ]
[ 1/5 ] [ 1/3 ] [ 7/15 ]
[4/15] [ 3/5 ] [ 2/15 ].
Excluding reflections and rotations, there is only one 3x3 magic square using 1-9.
By using the quadratic equation formula
If you are using square roots, the simplest way of solving: ax2 + bx + c = 0 is x = [-b ± sqrt(b2-4ac)]/(2a)
76 percent of 600 using fractions will be 76 600
simplification
write a vb program to find the magic square
The answer will depend on the exact nature of the equation.
123 123 123
Excluding reflections and rotations, there is only one 3x3 magic square using 1-9.
By using the quadratic equation formula
its impossible because in a 4 by 4 magic square u need 16 numbers u cant do it with just 0-9
Yes. One solution is: -4 16 -12 -8 0 8 12 -16 4
If you are using square roots, the simplest way of solving: ax2 + bx + c = 0 is x = [-b ± sqrt(b2-4ac)]/(2a)
Excluding rotations and reflections, there is only one 3x3 magic square.
its just using fractions but not more than once to make other fractions
76 percent of 600 using fractions will be 76 600
All rows, columns and diagonals must total the same number, which is the "magic number". You must enter the appropriate missing numbers to make this happen, using the number choices made available.