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Yes. One solution is:

-4 16 -12

-8 0 8

12 -16 4

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What is the magic square 3x3 answer - 18?

A 3x3 magic square has the property that the sum of the numbers in each row, column, and diagonal is the same. For a 3x3 magic square using the numbers 1 to 9, the magic constant is 15, not 18. If you're referring to a different set of numbers or a modified version of a magic square, please specify the numbers used to achieve a magic constant of 18.


3x3 magic square using positive and negative numbers?

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All rows, columns and diagonals must total the same number, which is the "magic number". You must enter the appropriate missing numbers to make this happen, using the number choices made available.


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Using 1-6 can a magic triangle have a sum of 13


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How do you solve 3 times 3 magic square numbers 1-9 each row column and diagonal totals a prime number?

To create a 3x3 magic square using the numbers 1-9 where each row, column, and diagonal sums to a prime number, you can start by arranging the numbers so that the magic constant (sum of each row, column, and diagonal) is 15, which is not prime. However, to achieve prime sums, you can explore variations by adjusting the placement of specific numbers. For example, one feasible arrangement is to use the numbers 1, 2, 3, 4, 5, 6, 7, 8, and 9 with specific placements to ensure all rows, columns, and diagonals total to prime numbers like 17 or 19, though achieving this with a strict magic square structure may require deviation from classic arrangements.


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[ -8 ] [ -1 ] [ -6 ][ -3 ] [ -5 ] [ -7 ][ -4 ] [ -9 ] [ -2 ]The sum of each row, column, and diagonal is -15.


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In an 8x8 magic square, the sum of each row, column, and diagonal is the same, known as the magic constant. For an n x n magic square, the magic constant can be calculated using the formula ( M = \frac{n(n^2 + 1)}{2} ). For an 8x8 magic square, this gives ( M = \frac{8(64 + 1)}{2} = 260 ). Therefore, the sum in the 1st row of an 8x8 magic square is 260.