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How do you solve a miner earns 1 cent the first day 2 cents and keeps doubling his pay for 30 days?
Wiki User
∙ 12y ago
day 1 $0.01
day 2 $0.02
day 3 $0.04
day 4 $0.08
day 5 $0.16
day 6 $0.32
day 7 $0.64
day 8 $1.28
day 9 $2.56
day 10 $5.12
day 11 $10.24
day 12 $20.48
day 13 $40.96
day 14 $81.92
day 15 $163.84
day 16 $327.68
day 17 $655.36
day 18 $1310.72
day 19 $2621.44
day 20 $5242.88
day 21 $10485.76
day 22 $20971.52
day 23 $41943.04
day 24 $83886.08
day 25 $167772.16
day 26 $335544.32
day 27 $671088.64
day 28 $1342177.28
day 29 $2684354.56
day 30 $5368709.12
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which you can set up an equation to find the amount on any particular day:
2(n-1)*$0.01, where n is the day.
So the sixth day would be 2(6-1)*$0.01 = 25*$0.01 = 32*$0.01 = $0.32 which is answer listed above for day 6.
Wiki User
∙ 12y ago
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