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day 1 $0.01

day 2 $0.02

day 3 $0.04

day 4 $0.08

day 5 $0.16

day 6 $0.32

day 7 $0.64

day 8 $1.28

day 9 $2.56

day 10 $5.12

day 11 $10.24

day 12 $20.48

day 13 $40.96

day 14 $81.92

day 15 $163.84

day 16 $327.68

day 17 $655.36

day 18 $1310.72

day 19 $2621.44

day 20 $5242.88

day 21 $10485.76

day 22 $20971.52

day 23 $41943.04

day 24 $83886.08

day 25 $167772.16

day 26 $335544.32

day 27 $671088.64

day 28 $1342177.28

day 29 $2684354.56

day 30 $5368709.12

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which you can set up an equation to find the amount on any particular day:

2(n-1)*$0.01, where n is the day.

So the sixth day would be 2(6-1)*$0.01 = 25*$0.01 = 32*$0.01 = $0.32 which is answer listed above for day 6.

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Q: How do you solve a miner earns 1 cent the first day 2 cents and keeps doubling his pay for 30 days?
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