Multiply length x width.
It depends on its size - which is not standard.
Volume of a rectangular prism = base x height. If volume and height are known, solve for base area by dividing volume by height.
Area of a rectangular prism = 2lw + 2lh + 2wh, where l is length, w is width, and h is height.
it depends on which size it is and how much matter it contains
There is no "height" of a rectangle, unless it's a rectangular prism. Do you mean the length? If you have the area of the rectangle, the equation should be:A= L x WPlug in the area and the length and solve for the width, or plug in the area the width of the rectangle, and solve for the length.
The equation for the surface area of a rectangular prism is: A = 2lw + 2lh + 2wh Replace the variables you know, and solve for the remaining variable.
Properties of a rectangular prism: * A rectangular prism has a total of 6 surfaces. * Because it is rectangular it will have 4 equal longer edges and 8 equal shorter edges, and so * It will have 4 rectangular faces and 2 square faces, therefore * Total surface area = 2 x square (end ) surface + 4 x rectangular (side) surfaces If we let x = shorter edges (breadth) & y = longer edges (length), and, as area = length x breadth, then * each end (a square surface) will have an area of x2 * each side (rectangular surface) will have an area of xy Thus: Total surface area of the rectangular prism = 2 x end area + 4 x side area = 2x2 + 4xy = 2x(x + 2y) Hope this nswers your question and explains how we arrive at the formula for calculating the total surface area of a rectangular prism.
Depends whether you want the formula for surface area, volume, perimeter, size of sphere it would fit into etc... Please clarify next time.
What are the 5th features of development of computer?
What are the 5th features of development of computer?
For the same base dimensions (base area) and the same height, the rectangular prism has more surface area.
The answer will depend on the shape (and size) of the box: some have a rectangular cross-section, others circular.