You substract 6 to -8 so its equal to
y over 6 equal -2 and the you multiply -2 by 6!
So the y equal -12...
Just divide both sides by 7...
7
112/8=n 14=n check= 8x14=112
Equations do not have "answers", a myth which is reinforced by the way algebra tends to be taught in schools. You can, however, solve equations for different things, particularly variables. If by the "answer", you mean the value of p, then we can solve it like this: 3.25p - 14 = 12 3.25p = 26 p = 26/3.25 p = 8
To solve equations like x2+a=0 with a>0
To solve -2 plus 5 equals, it's probably easier to start with the positive number and add the negative number to it. The equation will look like this: 5 + (-2) = Because you are adding a negative number, you actually have to subtract the 2, rather than add it, so your answer will be 3.
The answer is .0284278589. To solve you solve like a normal squared problem, just with a negative. So, on a calculator like a TI-83, you do this: 5.9310^-2
There isn't a universal way to do this, just like there isn't a universal way to solve nonlinear equations in one variable. A good place to start, however, would be to attempt to solve an equation for one of the variables, in terms of the other two. If you substitute that into the other equations, you will then have a system of two equations in two variables. Do this again, and you'll have a single variable equation that you'll hopefully know how to solve.
In a math equation, something equals something else. You haven't given any equation to work with. I'm thinking you're looking to find 'x' when 'y' equals 2, when 'y' equals 3, etc. But we need some more info to help you.
For the product to be zero, any of the factors must be zero, so you solve, separately, the two equations: sin x = 0 and: cos x = 0 Like many trigonometric equations, this will have an infinity of solutions, since sine and cosine are periodic functions.
First, if you have two equations like, for instance .90x+2000 and .40x+3500 then you would set them equal to each other like this ( .90x+2000=.40x+3500). Then you would solve for x by simplifying the equations as far down as you can.
It looks like you have 2 simultaneous equations with 2 variables:4x + 8y = 20 and -4x + 2y = -30. Solution is {x=7, y = -1}.One way to solve:Add the two equations together, combining like terms: (4x - 4x) + (8y + 2y) = 20-30 --> 0 + 10y = -10 --> y = -1. Substitute this into either of the original equations and solve for x=7, then check in the other equation to make sure you calculated correctly.