7
-3/4 if the question is 3x+4y
You cannot solve it since only one side of an equation is given. If the equation was y4 + 5y2 - 84 = 0 then y4 + 12y2 - 7y2 - 84 = 0 or y2*(y2 + 12) - 7*(y2 + 12) = 0 or (y2 - 7)*(y2 + 12) = 0 then y2 = 7 or y2 = - 12 y = +or- sqrt(7) and, if you are in the complex domain, also y = +or- i*sqrt(12) where i is the imaginary square root of -1.
To enter the equations ( x - y^4 ) and ( 3x - 5y^2 ) into a calculator for graphing or solving, you typically need to solve for ( y ) in terms of ( x ). For ( x - y^4 = 0 ), rearrange to ( y^4 = x ), giving ( y = x^{1/4} ). For ( 3x - 5y^2 = 0 ), rearrange to ( y^2 = \frac{3x}{5} ), leading to ( y = \sqrt{\frac{3x}{5}} ). Input these as ( y = x^{1/4} ) and ( y = \sqrt{\frac{3x}{5}} ) respectively.
x=y4 /2
Assuming the vertex is 0,0 and the directrix is y=4 x^2=0
The simplest equation would be y4 = 0
-3/4 if the question is 3x+4y
An equation is a statement that two things are equal; it has an equal sign which looks like this: = So if, for example, 2x + 5 = y4 - 27, that's an equation. A collection of numbers and/or letters that does not have an equal sign would be an expression. For example, 3x(9 + x).
You cannot solve it since only one side of an equation is given. If the equation was y4 + 5y2 - 84 = 0 then y4 + 12y2 - 7y2 - 84 = 0 or y2*(y2 + 12) - 7*(y2 + 12) = 0 or (y2 - 7)*(y2 + 12) = 0 then y2 = 7 or y2 = - 12 y = +or- sqrt(7) and, if you are in the complex domain, also y = +or- i*sqrt(12) where i is the imaginary square root of -1.
x-7*y*4 >> solve it * is multiply-
9y-81=9*(y-9)
No because it's not a simultaneous equation but some kind of algebraic expression
The GCF is y4
x=y4 /2
4x-y4 what = 0
Assuming the vertex is 0,0 and the directrix is y=4 x^2=0
(x2 + y2)(x + y)(x - y) = x4 - y4.