A system? Try elimination
3(8X - Y = 4)
5X + 3Y = 17
24X - 3Y = 12
5X + 3Y = 17
-------------------------+
29X = 29
X = 1
-----------find Y
8(1) - Y = 4
- Y = - 4
Y = - 1
-----------check
By inspection one can see this is inconsitent
you have 9n+17=-1 -17 -17 9n=-18 /9 /9 n= -2
(0,7)
(4 ± i2) where i2 = -1
119
-3+y=17+1 im assuming solve for y?-3+y=18 add 3 to both sidesy=21
24
you have 9n+17=-1 -17 -17 9n=-18 /9 /9 n= -2
(0,7)
(4 ± i2) where i2 = -1
119
The answer depends on what it is that you want to do. You cannot solve a single linear equation in two variables.
-3+y=17+1 im assuming solve for y?-3+y=18 add 3 to both sidesy=21
You can't. 17 + 2n = 21 + 2n gives: 2n = 4 + 2n which gives 0=4 which is not possible so the sum is not solveable.
-6x + 12y = -102 -6x = -12y - 102 x = 2y + 17
-2
In roman numerals, XII equals 12, and V equals 5. So as 12 plus 5 equals 17, XII plus V equals 17:) hope it helpedImproved Answer:XII+V = XVII (12+5 = 17)
-17 + y,,must be equals to..-17y..