Answer:12y=132y=132/12=11
12y+3=9y-15 3y=-18 y=-6
3y + 4z + 12y = 3y -3y -3y ------------------------- 4z + 12y = 0 divide everything by 4 z + 3y = 0 -3y -3y z = -3y
y = 11
x = 2 and y =-3 so the lines intersect at (2, -3)
12y - 4 = 7y + 165y = 20y = 4
12y+2=146 12y=146-2 12y=144 144/12 12x12=144 y=12
12y = 132y = 132/12y = 11
12y + 5 = 53 12y = 48 y = 4
Answer:12y=132y=132/12=11
2x + 12 y =36subtract 2x from both sides12y = 36 - 2xdivide both sides by 12y = (36 - 2x)/12
5*3y+1+12y-1 = 15y+1+12y-1 = 27y.
The given equation: =3x-4x plus 9xy-12y =3x-4x+9xy-12y =-x+9xy-12y =-x+3y(3y-4) Answer.
12y+3=9y-15 3y=-18 y=-6
12y = 8x + 24 so y = 2x/3 + 2
6y + 4.. i think
12y + 2 or 2*(6y+ 1)