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[log2 (x - 3)](log2 5) = 2log2 10

log2 (x - 3) = 2log2 10/log2 5

log2 (x - 3) = 2(log 10/log 2)/(log5/log 2)

log2 (x - 3) = 2(log 10/log 5)

log2 (x - 3) = 2(1/log 5)

log2 (x - 3) = 2/log 5

x - 3 = 22/log

x = 3 + 22/log 5

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Q: How do you solve log base 2 of x - 3 log base 2 of 5 equals 2 log base 2 of 10?
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