[log2 (x - 3)](log2 5) = 2log2 10
log2 (x - 3) = 2log2 10/log2 5
log2 (x - 3) = 2(log 10/log 2)/(log5/log 2)
log2 (x - 3) = 2(log 10/log 5)
log2 (x - 3) = 2(1/log 5)
log2 (x - 3) = 2/log 5
x - 3 = 22/log
x = 3 + 22/log 5
log(x)+log(8)=1 log(8x)=1 8x=e x=e/8 You're welcome. e is the irrational number 2.7....... Often log refers to base 10 and ln refers to base e, so the answer could be x=10/8
ln is the natural logarithm. That is it is defined as log base e. As we all know from school, log base 10 of 10 = 1 just as log base 3 of 3 = 1, so, likewise, log base e of e = 1 and 1.x = x. so we have ln y = x. Relace ln with log base e, and you should get y = ex
Take logs of both sides - you can use any base, to give the answer: 10^x = 97 → log(10^x) = log(97) → x log(10) = log(97) → x = log(97) ÷ log(10) If you use common logs (logs to base 10) - highly recommended in this case), then: lg(10) = 1 → x = lg(97)
Your calculator won't usually have a function to calculate logs in base 5 or base 8 directly, but this can easily be solved. For example: log5125 = log 125 / log 5 (taking both logs in base 10, or both logs in base e) In this particular case, you can also solve the equation mentally - you don't even need a calculator! Just use the definition of a log: "To what power must I raise 5 to get 125?" The answer to this is, by definition, log5125. Similarly with log28.
18.057299999999998
y = 10 y = log x (the base of the log is 10, common logarithm) 10 = log x so that, 10^10 = x 10,000,000,000 = x
log(x)+log(8)=1 log(8x)=1 8x=e x=e/8 You're welcome. e is the irrational number 2.7....... Often log refers to base 10 and ln refers to base e, so the answer could be x=10/8
ln is the natural logarithm. That is it is defined as log base e. As we all know from school, log base 10 of 10 = 1 just as log base 3 of 3 = 1, so, likewise, log base e of e = 1 and 1.x = x. so we have ln y = x. Relace ln with log base e, and you should get y = ex
Logs to base 10 are common logs and are abbreviated to lg; to solve use antilogs: lg x = 2 → 10^(lg x) = 10^2 → x = 10² = 100
250x = 400000 then x log 250 = log 400000 so x = log 400000 / log 250 Natural logs could have been used instead of logs to base 10.
log 100 base e = log 100 base 10 / log e base 10 log 100 base 10 = 10g 10^2 base 10 = 2 log 10 base 10 = 2 log e base 10 = 0.434294 (calculator) log 100 base e = 2/0.434294 = 4.605175
2 log(x) + 3 log(x) = 105 log(x) = 10log(x) = 10/5 = 210log(x) = (10)2x = 100
X is the log(to the base 2) of 10 = 3.324(rounded)
Take logs of both sides - you can use any base, to give the answer: 10^x = 97 → log(10^x) = log(97) → x log(10) = log(97) → x = log(97) ÷ log(10) If you use common logs (logs to base 10) - highly recommended in this case), then: lg(10) = 1 → x = lg(97)
Your calculator won't usually have a function to calculate logs in base 5 or base 8 directly, but this can easily be solved. For example: log5125 = log 125 / log 5 (taking both logs in base 10, or both logs in base e) In this particular case, you can also solve the equation mentally - you don't even need a calculator! Just use the definition of a log: "To what power must I raise 5 to get 125?" The answer to this is, by definition, log5125. Similarly with log28.
When the unknown is in the power you need to use logs (to any base) and the rule: log(a^b) = b × log(a) Thus: 10^x - 4 = 7 → 10^x = 11 → x log 10 = log 11 → x = log 11 ÷ log 10 If you use common logs (to base 10) then: lg 10 = 1 → x = lg 11 ≈ 1.04
18.057299999999998