It can't be solved because the discriminant of this quadratic equation is less than zero
a^(2) - b^(2) + ac - bc Factor ( a - b)( a + b) + c(a - b) Factor further (a - b)(a + b + c) Done!!!!!
(b-4) squared
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x^(2) - 10x + 16 = 0 Factors of '16', which are, 1,2,4,8,16. Select two numbers from this list that add/subtract to '10' . They are '2' and '8'. Setting up brackets ( x 2)(x 8) Since '16' is positive(+), then both signs must be the same. Since '10x' is negative (-) , then both signs are negative. Hence (x - 2)(x - 8 ) = 0 When x - 2 = 0 x = 2 & when x - 8 = 0 x = 8 So the two answers are ,2, & ,8, .
(3x-2)(x-2)
X=1
You have to put your heart into it!
This expression factors as x -1 quantity squared.
X= plus or minus 1
x = 25 / 3squared + 5
Two plus 3 minus 2 times 1 squared plus 4 times 16 squared minus 4 times 2 is equal to 1,019.
1