Q: How do you solve 3x squared minus 17 plus 10?

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If x squared -10 = 0 then x = the square root of 10

2

20x2 - 3x + 10 does not have any real factors.

(5x - 2)(x - 5)

12

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If x squared -10 = 0 then x = the square root of 10

2

3m plus 19. Change it if I am wrong!

20x2 - 3x + 10 does not have any real factors.

(5x - 2)(x - 5)

2x+8x-2=22 10x-2=22 10x+2=+2 10x=24 10/10=24/10 x=2.4

You fill in for x and solve the equation3(5)^2 - 2(5)15^2 - 10; now solve

12

x2-10 = 4x+11 x2-4x-10-11 = 0 x2-4x-21 = 0 (x+3)(x-7) = 0 x = -3 and x = 7

X squared - 3x - 10 = 0 (x-5) (x+2) = 0 x - 5 = 0 x + 2 = 0 X= 5 x = -2

Subtract the stuff on the right from the stuff on the left. Get 4x2 - 22x + 10 = 0 Factor that. 2(x - 5)(2x - 1) = 0 x = 5, 0.5 Check it. 125 - 60 + 10 = 25 + 50 (75 = 75) Check. 1.25 - 6 + 10 = 0.25 + 5 (5.25 = 5.25) Check.

x2+2x-120 = (x+12)(x-10) when factored