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n3 + 2n2 - 15n = 0 : extract n as a factor of all the left hand terms then,

n(n2 + 2n - 15) = 0 : the expression n2 + 2n - 15 can be factored as (n + 5)(n - 3) then,

n(n + 5)(n - 3) = 0 : This holds true when either n = 0, or n + 5 = 0 or n - 3 = 0

When n + 5 = 0 then n = -5 : When n - 3 = 0 then n = 3.

The solutions are n = 0 or n = -5 or n = 3.

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14y ago
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Q: How do you solve n3 plus 2n2 - 15n equals 0 by factoring?
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