n3 + 2n2 - 15n = 0 : extract n as a factor of all the left hand terms then,
n(n2 + 2n - 15) = 0 : the expression n2 + 2n - 15 can be factored as (n + 5)(n - 3) then,
n(n + 5)(n - 3) = 0 : This holds true when either n = 0, or n + 5 = 0 or n - 3 = 0
When n + 5 = 0 then n = -5 : When n - 3 = 0 then n = 3.
The solutions are n = 0 or n = -5 or n = 3.
n - 15 = 86n = 86 + 15n = 101
-5 -15n = 10add 5 to both sides-15n = 15divide both sides by -15n = -1
when n = 0 it equals -25 when n = 1 it equals -36 when n = 2 it equals -39 etc
12m + 9n - 4 - 10m + 6n = 2m + 15n - 4
you wanna find out 15n=1275 you have to find out what times what equals 1275 alright =) by a fifth grader Majd Merai =) i rock hehehe
n - 15 = 86n = 86 + 15n = 101
-24
-5 -15n = 10add 5 to both sides-15n = 15divide both sides by -15n = -1
15n + 5 or 5(3n + 1)
6+5n=2n-9Isolate the variable by subtracting 2n and 6 from both sides.5n-2n=-9-63n=-15n=-5
(2n - 3)(n - 6)
2n2 + 15n + 7 = 2n2 + n + 14n + 7 = (2n2 + n) + (14n + 7) = n(2n + 1) + 7(2n + 1) = (2n + 1)(n + 7)
when n = 0 it equals -25 when n = 1 it equals -36 when n = 2 it equals -39 etc
12m + 9n - 4 - 10m + 6n = 2m + 15n - 4
24
11m + 6n - 2m + 9n = 9m + 15n or 3(3m + 5n)
you wanna find out 15n=1275 you have to find out what times what equals 1275 alright =) by a fifth grader Majd Merai =) i rock hehehe