(2n - 3)(n - 6)
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No, 18 is a multiple of 3. 3 is a factor of 18.
X^2 + 7X + 18 = 0 try the discriminant b^2 - 4ac 7^2 - 4(1)(18) 49 - 72 < 0 so, no real roots and no factors of 18 add to 7
16 + 16 + 16 + 17 + 18 + 18 + 18 + 19 + 19 + 20 + 20 + 20 + 21 = 238
If you're solving for b, then you use the quadratic formula to factor out b. In this case, b= -1/4 or -18/12
No, because 4 does not fit into 18 evenly.