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How do you solve one half log sub 7 x equals log sub 7 20 minus 2 parenthesis log sub 7 2 plus log sub 7 5 parenthesis?
Kiwi215
When solving this problem:
1/2log7x = log720 - 2(log72 + log75)
There are two things to note:
- lognx + logny = logn(xy)
- a(lognx) = lognxa
Using those two rules, we can simplify the given expression:
1/2log7x = log720 - 2(log72 + log75)
log7x1/2 = log720 - 2(log710)
log7x1/2 = log720 - log7102
log7x1/2 = log720 - log7100
log7x1/2 = log7(1/5)
√x = 1/5
x = 1/25
Wiki User
∙ 12y ago
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