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Q: How do you solve the area of a trapezium?

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area of trapezium=1/2{a+b}h

Area = 0.5*(sum of parallel sides)*heightNote: A trapezium in the UK is known as a trapezoid in the USA

The area of a trapezium is found because: 0.5*(sum of parallel sides)*height = area

Area = 0.5*(sum of parallel sides)*heightNote: A trapezium in the UK is known as a trapezoid in the USA

Let the two parallel sides be a and b, and the distance between them, the height of the trapezium, be h. Then: area of trapezium = 1/2 (a+b) h That is half the sum of the two parallel sides times the height of the trapezium.

The area of a trapezium is given by 0.5*(a+b)*h where a and b are the lengths of the parallel sides and h is the vertical distance between them. The fact that the trapezium is isosceles does not matter. A trapezium is a 2 dimensional object and so it has no volume.

0.5 * (a + b) * h

base multiply by height

1. C program or source code for find area of trapezium2. How to calculate area of trapezium in c programming language#includeint main(){floatheight,base1,base2;float area;printf("Enter the height of the trapezium: ");scanf("%f%",&height);printf("Enter length of lower base of the trapezium: ");scanf("%f%",&base1);printf("Enter length of upper base of the trapezium: ");scanf("%f%",&base2);area = 0.5 * (base1 + base2) * height;printf("Area of trapezium is: %f",area);return 0;}

You do not need to transpose anything to get the formula for the area of a trapezium! (I need the transpose the formula so a is the subject thank you)

It's 54

A trapezium is a 2-dimensional shape and so has no volume. If you were thinking of area, there is not enough information to answer.

base times height divide 2

A trapezium. A trapezium. A trapezium. A trapezium.

Area of a trapezium = 0.5*(sum of parallel sides)*height

Area = 1/2*(sum of the parallel sides)*height

Simple. It is zero, since a six sided trapezium cannot exist! By definition, a trapezium is a quadrilateral and so it can have exactly four sides - no more, no fewer!

The information given describes a square and not a trapezium. Area of the square = 3*3 = 9 square cm

divide the trapesium into a rectangle and two triangles if you can find the area of triangles

200.106m2

½×(sum of parallel sides)×(distance between them)

a+b-h\2

If the two parallel side of the trapezium are a and b and height of the trapezium (the distance between the parallel sides) is h then the area is given by:Area = 1/2 (a + b) x hHalf the sum of the lengths of the parallel sides times the distance between them.

Suppose the base and parallel sides of the trapezium are labelled a and b. Suppose, also, that the distance between a and b is h. Draw a diagonal. This will split the trapezium into one triangle whose base is the trapezium's base (a) and another upside-down triangle whose base is the trapezium's top (b). The heights of both these triangles will be the same as the distance between the parallel sides of the trapezium (h). The area of the first triangle is 0.5*a*h The area of the second triangle is 0.5*b*h So the area of the trapezium = 0.5*a*h + 0.5*b*h = 0.5*(a+b)*h

Area = (1/2)*(sum of the parallel sides)*(distance between them)