Simple. It is zero, since a six sided trapezium cannot exist! By definition, a trapezium is a quadrilateral and so it can have exactly four sides - no more, no fewer!
The area of a trapezium is found because: 0.5*(sum of parallel sides)*height = area
Let the two parallel sides be a and b, and the distance between them, the height of the trapezium, be h. Then: area of trapezium = 1/2 (a+b) h That is half the sum of the two parallel sides times the height of the trapezium.
If the two parallel sides are of length a and b, and the vertical distance between them is h then area = h*(a+b)/2 square units.
The information given describes a square and not a trapezium. Area of the square = 3*3 = 9 square cm
Area of a trapezium = 0.5*(sum of parallel sides)*height
Area = 1/2*(sum of the parallel sides)*height
1 - (a+b) X h 2
Simple. It is zero, since a six sided trapezium cannot exist! By definition, a trapezium is a quadrilateral and so it can have exactly four sides - no more, no fewer!
1/2 x (sum of bases) x height
area of trapezium=1/2{a+b}h
Area = 0.5*(sum of parallel sides)*heightNote: A trapezium in the UK is known as a trapezoid in the USA
The area of a trapezium is found because: 0.5*(sum of parallel sides)*height = area
Let the two parallel sides be a and b, and the distance between them, the height of the trapezium, be h. Then: area of trapezium = 1/2 (a+b) h That is half the sum of the two parallel sides times the height of the trapezium.
Area = 0.5*(sum of parallel sides)*heightNote: A trapezium in the UK is known as a trapezoid in the USA
Area = a [(b1 + b2)/2]a = altitude (height) of the trapezoidb1 = length of one baseb2 = length of the other base
The area of a trapezium is given by 0.5*(a+b)*h where a and b are the lengths of the parallel sides and h is the vertical distance between them. The fact that the trapezium is isosceles does not matter. A trapezium is a 2 dimensional object and so it has no volume.