Let the two parallel sides be a and b, and the distance between them, the height of the trapezium, be h. Then:
area of trapezium = 1/2 (a+b) h
That is half the sum of the two parallel sides times the height of the trapezium.
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The area of a trapezium is found because: 0.5*(sum of parallel sides)*height = area
0.5 * (a + b) * h
Simple. It is zero, since a six sided trapezium cannot exist! By definition, a trapezium is a quadrilateral and so it can have exactly four sides - no more, no fewer!
The information given describes a square and not a trapezium. Area of the square = 3*3 = 9 square cm
If the two parallel side of the trapezium are a and b and height of the trapezium (the distance between the parallel sides) is h then the area is given by:Area = 1/2 (a + b) x hHalf the sum of the lengths of the parallel sides times the distance between them.