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Q: How do you solve the equation 7w plus 2 equals 3w plus 94?

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You can't solve it - you only have one equation and two unknowns. You need 2 equations to solve this.

3w + 4 = 24 .......- 4... - 4 .......3w = 20 .......÷3 ...÷3 .........w = 20/3 or 6.6667

Try like this:4 = 3w - 5Add 5 to each side of the equation:9 = 3wDivide each side by 3:3 = w

3w^2 - 8w + 4 = (3w -2) (w-2) So 3w-2=0, then 3w=2, so w=2/3, w-2=0, so w=2. Your solutions are w=2/3 and w=2.

Factor it. If that's -8w, it factors to (w - 2)(3w - 2) w = 2, 2/3 If that's +8w, it factors to (w + 2)(3w + 2) w = -2, -2/3

This is an example of the "commutative" property.

Without an equality sign the given expression can't be considered to be an equation

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That's not an equation. It need a = sign before you can solve it. However you can simplify it by combining like factors

7W + 4 - 3W = 15gather the w's together4W + 4 = 15subtract 4 from each side4W = 11divide each sides integers by 4W = 11/4================checks

3w - 2 = 2w + 3 Add 2 to both sides: 3w = 2w + 5 Subtract 2w from both sides: w = 5

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5w - 5 = 8w - 25 -5 + 25 = 8w - 5w 20 = 3w 6 2/3 = w

If: 3w = 42 Then: w = 14

3w + 12

7+3w-13x

3w -6 = -15 3w = -15+6 3w = -9 w = -3

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15x+12y+22+3w-2y+3x+14-12+3w original = 15x+3x+12y-2y+3w+3w+22+14-12 group = 18x+10y+6w+24 answer

4(w^2 + 3w + 1)

If: 3w-17 = 4 Then: w = 7

If you mean sqrt (3w +13) = sqrt(5w-7) with all terms under the radical, then just square both sides. then; 3w+13 = 5w-7 ( subtract 3w from each side ) 13 = 2w-7 ( add 7 to both sides ) 20 = 2w 10 = w

w + 3 = 4w - 6 9 = 3w w = 3

3w + 4e + 7w - e3 = 10w - e

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