7w + 2 = 3w + 94 Subtract 3w from both sides: 4w + 2 = 94 Subtract 2 from both sides: 4w = 92 Divide both sides by 4: w = 23
w = 3 16 = 4w + 2w - 2 Move the 2 to other side 16 + 2 = 4w + 2w 18 = 6w 18 / 6 = 3 = w
w = 6 Please remember to click the trust button below to make me feel good (if answer is correct) :)
P=2W+2L 256=2W+2(3W) 256=2W+6W 256=8W Divide by 8 on both sides 32=W
You can come up with 2 equations 1) L + 3 = 2w 2) L X W = 35 Rearrange the first equation so it is L= 2w - 3 then substitute into the second equation. (2w - 3)w = 35 2w2-3w =35 from here we need to factor 2w2-3w-35 (2x+7)(x-5) This means that x either equals -2/7 (impossible) or 5 Since the width is 5 the length is 7 which can be checked by plugging the two numbers into the two original equations
5w+2 = 2w+5 5w-2w = 5-2 3w = 3 w = 1
(3w + 2)(2w + 5) so w = -2/3 or -2.5
This is an example of the "commutative" property.
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x = (P - 2W) / 2
a = L x W: area equals length times the width. p = 2L + 2W: perimeter equals 2 times the length plus 2 times the width so L = (p - 2W)/2
7w + 2 = 3w + 94 Subtract 3w from both sides: 4w + 2 = 94 Subtract 2 from both sides: 4w = 92 Divide both sides by 4: w = 23
You have an two equations: L = 3W and 2L+2W=96. This is two unknowns and two equations, so this is solvable. Since L=3W, you can perform a simple substitution to derive 2(3W) + 2W = 96 6W +2W = 96 8W = 96. So W = 12 and L=36.
7+3w-13x
w = 3 16 = 4w + 2w - 2 Move the 2 to other side 16 + 2 = 4w + 2w 18 = 6w 18 / 6 = 3 = w
2L+2W=P (S2w) Subtract 2W from both sides 2L=P-2W (D2) Divide both sides by 2 L=(P-2W)/2
3w^2 - 8w + 4 = (3w -2) (w-2) So 3w-2=0, then 3w=2, so w=2/3, w-2=0, so w=2. Your solutions are w=2/3 and w=2.