7w + 2 = 3w + 94 Subtract 3w from both sides: 4w + 2 = 94 Subtract 2 from both sides: 4w = 92 Divide both sides by 4: w = 23
15x+12y+22+3w-2y+3x+14-12+3w original = 15x+3x+12y-2y+3w+3w+22+14-12 group = 18x+10y+6w+24 answer
3w - 2 = 2w + 3 Add 2 to both sides: 3w = 2w + 5 Subtract 2w from both sides: w = 5
102
3w -6 = -15 3w = -15+6 3w = -9 w = -3
You can't solve it - you only have one equation and two unknowns. You need 2 equations to solve this.
This is an example of the "commutative" property.
7w + 2 = 3w + 94 Subtract 3w from both sides: 4w + 2 = 94 Subtract 2 from both sides: 4w = 92 Divide both sides by 4: w = 23
t
15x+12y+22+3w-2y+3x+14-12+3w original = 15x+3x+12y-2y+3w+3w+22+14-12 group = 18x+10y+6w+24 answer
7W + 4 - 3W = 15gather the w's together4W + 4 = 15subtract 4 from each side4W = 11divide each sides integers by 4W = 11/4================checks
3w - 2 = 2w + 3 Add 2 to both sides: 3w = 2w + 5 Subtract 2w from both sides: w = 5
102
Try like this:4 = 3w - 5Add 5 to each side of the equation:9 = 3wDivide each side by 3:3 = w
If you mean sqrt (3w +13) = sqrt(5w-7) with all terms under the radical, then just square both sides. then; 3w+13 = 5w-7 ( subtract 3w from each side ) 13 = 2w-7 ( add 7 to both sides ) 20 = 2w 10 = w
If: 3w = 42 Then: w = 14
11