[ 3x2 - 7x - 20 ] is not a problem, and needs no solution. It's just an expression that
stands for a number, and there's no way to find out what the number is until you know
what number 'x' is.
If you had said that this expression is equal tosomething, then you'd have an equation,
and you could ask us to find what number 'x' must be in order to make the equation a
true statement. But all you have just now is a number, that depends on the value of 'x'.
3x2 - 7x - 20 = (3x + 5)(x - 4)
If you mean 3x2-7x+x = -4 then there are no solutions because the discriminant of the quadratic equation is less than zero.
3x2-7x-20 = (3x+5)(x-4) when factored
(3x + 5)(x - 4)
(3x - 5)(x + 4)
(x + 4)(3x - 5)
7x = 20 + 4xSubtract 4x from each side of the equation:3x = 20Divide each side by 3 :x = 20/3
-29
3x2-7x+4 = (3x-4)(x-1) when factored
2y + 7x + y-1?
3x^2 + 7 x =20 3x^2 + 7x - 20 = 0 3(-4)^2 + 7(-4) -20 3(16) -28 -20 48-28-20 = 0 (-4) 3x^2 + 7x =20 3(1.666)^2 + 7(1.666) -20 =0 3(2.78) + 11.66 - 20 =0 8.34 + 11.66 - 20 = 0 (1.666 or 5/3) answers (-4, 5/3)
(21x3-23x2-76x-32)/(7x+4) = [3x2(7x4) -5x(7x+4)-8(7x+4)]/(7x+4)=3x2-5x-8