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How do you solve the square root of 3 to the power of n plus 1?
Wiki User
∙ 11y ago
As you may know, multiplying and dividing powers of the same number (for example, 2^2 x 2^3), you add and subtract the exponents (in this case, 2+3=5, so 2^5). Your question has a variable in the problem. If you have a value for "n", this problem will come out to a whole number IF it's an odd value, because to get the square root of a number to an exponent, you divide the exponent by two. In your case, let's say "n"=7. 3^n+1=3^7+1=3^8, or 6561. To take the square root, divide the exponent (8) by two, so √3^8=3^4, or 81. Hope this helps.
Wiki User
∙ 11y ago
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