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How do you solve these two equations 5y equals x-10 and 3y plus x equals 2?
Wiki User
∙ 14y ago
5y = x - 10 and 3y +x = 2 There are two ways to solve this: elimination and substitution. First move the systems into something more manageable: 5y - x = -10 and 3y +x = 2 If you write the two on top of one another you notice that if you were to add them the two X's would cancel. +x + -x = 0. This is elimination. writing the new system after the adding yields 8y = -8 therefore Y = -1. you can input Y now and solve for X. 5(-1) = x - 10. therefore X = 5. the second way is substitution. solve one of the systems for one of the variables. 3y + x = 2 therefore x = 2 - 3y. now input that value in for X in the other equation. 5y = (2 - 3y) - 10. solving this yields 8y = -8 once again proving that Y = -1. again substitute that value into either equation to find X
Wiki User
∙ 14y ago
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