By elimination: x = 3 and y = 0
(2,-2)
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
You cannot solve one linear equation in two variables. You need two equations that are independent.
Yes and it works out that x = 3 and y = 4
By elimination: x = 3 and y = 0
(2,-2)
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
You cannot solve one linear equation in two variables. You need two equations that are independent.
Yes and it works out that x = 3 and y = 4
X=0 and y=0
Multiply every term in both equations by any number that is not 0 or 1, and has not been posted in our discussion already. Then solve the new system you have created using elimination or substitution method:6x + 9y = -310x - 6y = 58
4
You use algebra and solve the system(s) of equations using techniques such as elimination or substitution.
the answer
One way to solve this system of equations is by using matrices. Form an augmented matrix in which the first 2x2 matrix is the coefficient matrix and the 2x1 matrix on its right is the answer. Now apply Gaussian Elimination and back-substitution. Using this method gives x=5 and y=1.
You can solve lineaar quadratic systems by either the elimination or the substitution methods. You can also solve them using the comparison method. Which method works best depends on which method the person solving them is comfortable with.