You cannot solve one linear equation in two variables. You need two equations that are independent.
By elimination: x = 3 and y = 0
(2,-2)
Yes and it works out that x = 3 and y = 4
y=16 x= -4
No. Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
By elimination: x = 3 and y = 0
(2,-2)
Yes and it works out that x = 3 and y = 4
y=16 x= -4
The elimination method only works with simultaneous equations, hence another equation is needed here for it to be solvable.
No. Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
16
The answer is that it cannot be done. To solve a set of equations in k variables (in this case, 2) you need at least two independent equations.
The given expression can't be solved as equations because there are no equality signs.
x^(2) - 10x + 16 = 0 Factors of '16', which are, 1,2,4,8,16. Select two numbers from this list that add/subtract to '10' . They are '2' and '8'. Setting up brackets ( x 2)(x 8) Since '16' is positive(+), then both signs must be the same. Since '10x' is negative (-) , then both signs are negative. Hence (x - 2)(x - 8 ) = 0 When x - 2 = 0 x = 2 & when x - 8 = 0 x = 8 So the two answers are ,2, & ,8, .
How do you solve 4y plus x equals 8
a=5: c=4