19 = f + 5
Subtract 5 from both sides: 14 = f
4y + 7 = 19 ∴ 4y = 12 ∴ y = 3
The answer to the equation 9 plus 5 times 0 equals 45. This was taught in 5 grade math.
It's a linear equation in 'x'.To solve it:x + 19 = 42Subtract 19 from each side of the equation:x = 23
9a-a = 19+7a 8a = 19+7a 8a - 7a = 19 + 7a - 7a 1a = 19 a = 19
You cannot solve it since it is not a true equation.
A is 14
You add 12... r + (-12) = 19 r + (-12) + 12 = 19 + 12 r = 31
An equation where x equals 3.
x = 19
It is an equation and the value of x is 7/19
-1-2x-4x=19-6x-1 = -19x = 3
19-2t = 7 -2t = 7-19 -2t = -12 t = 6