13
7
Equations: 2x-3y = 4 and 5x+2y = 1 Multiply all terms in 1st equation by 5 and all terms in 2nd equation by 2:- So: 10x-15y = 20 and 10x+4y = 2 Subtract the 2nd equation from the 1st equation: -19y = 18 => y = -18/19 By substitution the solutions are: x = 11/19 and y = -18/19
-49
x = 45 x 100/19 = 236.84
You cannot solve it since it is not a true equation.
4y + 7 = 19 ∴ 4y = 12 ∴ y = 3
19-2t = 7 -2t = 7-19 -2t = -12 t = 6
19 = f + 5 Subtract 5 from both sides: 14 = f
9a-a = 19+7a 8a = 19+7a 8a - 7a = 19 + 7a - 7a 1a = 19 a = 19
It's a linear equation in 'x'.To solve it:x + 19 = 42Subtract 19 from each side of the equation:x = 23
13
how do you set the equation in algebra to solve 42 nickles to 19 dimes
The answer to the equation 9 plus 5 times 0 equals 45. This was taught in 5 grade math.
You add 12... r + (-12) = 19 r + (-12) + 12 = 19 + 12 r = 31
An equation where p = 19
-108