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9x + 2y = 5

y - 2x + 3 = 0

Put both equations into the same format. It is often easiest to have just one unknown on (say) the left-hand side of the equation. Let's pick y for this purpose.

2y = -9x + 5

y = 2x - 3

Now make the coeficients of y the same. This can be done by multiplying the 2nd equation by 2.

2y = -9x + 5

2y = 4x - 6

Then, -9x + 5 = 4x - 6

13x = 11 : x = 11/13

And substitue for x in any equation - take the very first original equation.

9x + 2y = 5

99/13 + 2y = 5 : 2y = 5 - 78/13 = - 28/13

y = - 14/13

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Q: How do you solve this system algebracally 9x plus 2y equals 5 and y-2x plus 3 equals 0?
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