x=-2
-2 plus 5 equals +3
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
(xn+2-1)/(x2-1)
(x - 1)(x^2 - 5x + 2)
3 + 2 + 25*3 - 6 = 3 + 2 + 75 - 6 = 74
3
3
x3 + 8 = 0, then x3 = -8, therefore x = -2 -2 x -2 = 4 4 x -2 = -8
n= -2
The answer is x = 2.
x+2) by Algebraica Long Division. x^(3) + 3x^(2) + 3x + 2 ) = x^(2) + x + 1 -x^(3)- 2x^(2) ¬ 0 + x^(2) + 3x 0 - x^(2) - 2x ¬ 0 + 0 + x + 2 0 + 0 - x - 2 ¬ = 0 Hence answer is x^)2) + x + 1 ( Thos does NOT factor .
(a) y = -3x + 1