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If: x+y = 79 Then: y = 79-x
If: xy = 1288 Then: x(79-x) = 1288 and it follows that: 79x-x2-1288 = 0
Solving the above quadtratic equation gives x a value of 23 or 56
So the values are x = 23 and y = 56
Check: 23+56 = 79 and 23*56 = 1288
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∙ 12y ago
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