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If: x+y = 79 Then: y = 79-x

If: xy = 1288 Then: x(79-x) = 1288 and it follows that: 79x-x2-1288 = 0

Solving the above quadtratic equation gives x a value of 23 or 56

So the values are x = 23 and y = 56

Check: 23+56 = 79 and 23*56 = 1288

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Q: How do you solve x plus y equal 79 and xy equals 1288?
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