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Q: Solve this equation -9h - 6 plus 12h plus 40 equals 22?

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12h-17-h+16-2h =12h-3h-17+16 =9h-1,if you mean the value of h,then h =1/9

0 or 1 , a pulse that occurs once every 12 hours 55 minutes will have a slightly less than 1 in 3 chance of occurring during any random 4 hour 26 min. period. (4 hrs 26 min is slightly more than 1/3 of 12 hour 55 min) so a pulse, or lack of a pulse, during that period will have a value of 1 or 0. If, however, this is a typographical error then 12h 55m + 4hr 26m = 17hr 21min.

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h= -4

h=8

-9h-6+12h+40=22 -9h+12h=22-40+6 3h=-12 h=-4

-9h - 6 + 12h + 40 = 22 ie 3h = 22 + 6 - 40 h= -12/3 = -4

-9-6+12h+40=22

-9h-6+12h+40=22

-9h - 6 + 12h + 40 = 22, simplifying this gives12h - 9h + 40 - 6 = 223h + 34 = 22, taking 34 off both sides gives3h + 34 - 34 = 22 - 343h = -12, thush = -12/3 = -4

It is not an equation because there's no equal sign but some kind of algebraic expression.

h-9h-6+12h+40 = 22 h-9h+12h = 22+6-40 4h = -12 h = -3

It is: 12h+5h = 17h

-9h-6+12h+40 = 22 3h+34 = 22 3h = 22-34 3h = -12 h = -4

19h which = 7PM in the evening

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