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If x squared -10 = 0 then x = the square root of 10

Q: How do you solve x squared minus 10 equals 0?

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(3x-2)(x-2)

(x-5)(x+3)

10 squared equals 100. 102 = 10*10 10*10 = 100

h/(-3 - 7) = 10h/-10 = 10h = -100

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You fill in for x and solve the equation3(5)^2 - 2(5)15^2 - 10; now solve

(3x-2)(x-2)

1566 = x

(x-5)(x+3)

2x+8x-2=22 10x-2=22 10x+2=+2 10x=24 10/10=24/10 x=2.4

10 squared equals 100. 102 = 10*10 10*10 = 100

x2-10 = 4x+11 x2-4x-10-11 = 0 x2-4x-21 = 0 (x+3)(x-7) = 0 x = -3 and x = 7

7a=2(-10)........................................answer is 20/7

h/(-3 - 7) = 10h/-10 = 10h = -100

X squared - 3x - 10 = 0 (x-5) (x+2) = 0 x - 5 = 0 x + 2 = 0 X= 5 x = -2

-10x = -50 Divide both sides by -10 remembering that a minus divided by a minus the quotient then becomes positive: x = 5 So: -10*5 = -50