Recall that the antiderivative of 1/(1+x2) is arctan(x).
arctan(negative infinity) = -pi/2.
arctan(4) = approximately 1.325818.
The answer then is arctan(4) - (pi/2) = approximately -0.244979
Negative infinity plus negative infinity equals negative infinity.
It Is
Negative infinity plus one.
No.Unless the slope is zero, every line will extend from minus infinity to plus infinity. So part of it will be negative and part positive.No.Unless the slope is zero, every line will extend from minus infinity to plus infinity. So part of it will be negative and part positive.No.Unless the slope is zero, every line will extend from minus infinity to plus infinity. So part of it will be negative and part positive.No.Unless the slope is zero, every line will extend from minus infinity to plus infinity. So part of it will be negative and part positive.
Both extend from negative infinity to positive infinity.
The domain is from negative infinity to positive infinity. The range is from positive 2 to positive infinity.
Infinity plus infinity is without beginning nor ending
infinity
infinity!
infinity
NO BECAUSE YOU CAN ALWAYS SAY INFINITY PLUS ONE!
The Integral diverges. It has singularities whenever sin(x)+cos(x)=0. Singularities do not necessarily imply that the integral goes to infinity, but that is the case here, since the indefinite integral is x/2 + 1/2 Log[-Cos[x] - Sin[x]]. Obviously this diverges when evaluated at zero and 2pi.