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How do you tell if a quadratic function is minimum value or a maximum vale?
Wiki User
∙ 14y ago
Standard notation for a quadratic function:
y= ax2 + bx + c
which forms a parabola,
a is positive , minimum value (parabola opens upwards on an x-y graph)
a is negative, maximum value (parabola opens downward)
See related link.
Wiki User
∙ 14y ago
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What is the vertex of the quadratic function?
It if the max or minimum value.
How do you find the max and min in a quadratic equation?
A quadratic function is of the form: f(x) = ax2 + bx + c where a ≠0 If a > 0 then the quadratic has a minimum but its maximum, asymptotically, is +∞. If a < 0 then the quadratic has a maximum but its minimum, asymptotically, is -∞. The extremum (whichever it is) is attained when x = -b/2a. The extreme value is f(-b/2a) = a*(-b/2a)2 + b(-b/2a) + c = b2/4a - b2/2a + c = -b2/4a + c
How do you find the range and domain of a graph function?
Assuming the standard x and y axes, the range is the maximum value of y minus minimum value of y; and the domain is the maximum value of x minus minimum value of x.
What is maximum value and minimum value?
pi value= 1
When a feasible region is bounded on all sides where will the maximum and minimum values of the objective function occur?
Surely, you should check the value of the function at the boundaries of the region first. Rest depends on what the function is.
How do you determine wheather a quadratic function has a maximum or minimum and how do you find it?
In theory you can go down the differentiation route but because it is a quadratic, there is a simpler solution. The general form of a quadratic equation is y = ax2 + bx + c If a > 0 then the quadratic has a minimum If a < 0 then the quadratic has a maximum [and if a = 0 it is not a quadratic!] The maximum or minimum is attained when x = -b/2a and you evaluate y = ax2 + bx + c at this value of x to find the maximum or minimum value of the quadratic.
How do you determine if the graph of a quadratic function has a min or max from its equation?
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
What is the vertex of the quadratic function?
It if the max or minimum value.
How do you know if a quadratic has a minimum or maximum value?
When the quadratic is written in the form: y = ax2 + bx + c then if a > 0 y has a minimum if a < 0 y has a maximum and if a = 0 y is not a quadratic but y = bx + c, and it is linear. The maximum or minimum is at x = -b/(2a)
How will you describe the graph of a function?
· whether it is linear, quadratic or exponential · whether it has an upper or lower bound · whether it has a minimum or a maximum value · whether it is constant, decreasing or increasing
What is an extreme value in a set?
the maximum or minimum value of a continuous function on a set.
What is the maximum value that the graph of ycosx assume?
Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
How do you find minimum and maximum value of calculus?
In Calculus, to find the maximum and minimum value, you first take the derivative of the function then find the zeroes or the roots of it. Once you have the roots, you can just simply plug in the x value to the original function where y is the maximum or minimum value. To know if its a maximum or minimum value, simply do your number line to check. the x and y are now your max/min points/ coordinates.
How can you use the zeros of a function to find the maximum or minimum value of the function?
You cannot. The function f(x) = x2 + 1 has no real zeros. But it does have a minimum.
How do you find the max and min in a quadratic equation?
A quadratic function is of the form: f(x) = ax2 + bx + c where a ≠0 If a > 0 then the quadratic has a minimum but its maximum, asymptotically, is +∞. If a < 0 then the quadratic has a maximum but its minimum, asymptotically, is -∞. The extremum (whichever it is) is attained when x = -b/2a. The extreme value is f(-b/2a) = a*(-b/2a)2 + b(-b/2a) + c = b2/4a - b2/2a + c = -b2/4a + c
How do you find maximum height when working with quadratic equations?
In a quadratic equation, the vertex (which will be the maximum value of a negative quadratic and the minimum value of a positive quadratic) is in the exact center of any two x values whose corresponding y values are equal. So, you'd start by solving for x, given any y value in the function's range. Then, you'd solve for y where x equals the middle value of the two x's given in the previous. For example:y = x24 = x2x = 2, -2y = (0)2y = 0Which is, indeed, the vertex of y = x2
Are there no real solutions if a quadratic function is 0?
If a quadratic function is 0 for any value of the variable, then that value is a solution.
