In theory you can go down the differentiation route but because it is a quadratic, there is a simpler solution.
The general form of a quadratic equation is y = ax2 + bx + c
If a > 0 then the quadratic has a minimum
If a < 0 then the quadratic has a maximum
[and if a = 0 it is not a quadratic!]
The maximum or minimum is attained when x = -b/2a and you evaluate y = ax2 + bx + c at this value of x to find the maximum or minimum value of the quadratic.
Two.
The vertex.
Apex.
Addition is the maximum or minimum function in math.
Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
A quadratic of the form ax2 + bx + c has no maximum if a > 0: it gets infinitely large. If a = 0 then it is not a quadratic. If a < 0 then the quadratic does have a maximum, and it is -D/4a where D is the discriminant = b2 - 4ac
The minimum is the vertex which in this case is 0,0 or the origin. There isn't a maximum.....
A quadratic function can only have either a maximum or a minimum point, not both. The shape of the graph, which is a parabola, determines this: if the parabola opens upwards (the coefficient of the (x^2) term is positive), it has a minimum point; if it opens downwards (the coefficient is negative), it has a maximum point. Therefore, a quadratic function cannot exhibit both extreme values simultaneously.
It can't - unless you analyze the function restricted to a certain interval.
Two.
The "maximum" function.
vertex
Standard notation for a quadratic function: y= ax2 + bx + c which forms a parabola, a is positive , minimum value (parabola opens upwards on an x-y graph) a is negative, maximum value (parabola opens downward) See related link.
Find the maximum and minimum values that the function can take over all the values in the domain for the input. The range is the maximum minus the minimum.
Yes
When the quadratic is written in the form: y = ax2 + bx + c then if a > 0 y has a minimum if a < 0 y has a maximum and if a = 0 y is not a quadratic but y = bx + c, and it is linear. The maximum or minimum is at x = -b/(2a)